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2x+18=5x^2
We move all terms to the left:
2x+18-(5x^2)=0
determiningTheFunctionDomain -5x^2+2x+18=0
a = -5; b = 2; c = +18;
Δ = b2-4ac
Δ = 22-4·(-5)·18
Δ = 364
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{364}=\sqrt{4*91}=\sqrt{4}*\sqrt{91}=2\sqrt{91}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-2\sqrt{91}}{2*-5}=\frac{-2-2\sqrt{91}}{-10} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+2\sqrt{91}}{2*-5}=\frac{-2+2\sqrt{91}}{-10} $
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